What is the correct order comparing the acid strengths of $HF$,$HCl$,$HBr$,and $HI$?

  • A
    $HF >> HCl >> HBr >> HI$
  • B
    $HF << HCl << HBr << HI$
  • C
    $HF > HCl >> HBr >> HI$
  • D
    $HF << HCl >> HBr >> HI$

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The first $(\Delta_{i} H_{1})$ and the second $(\Delta_{i} H_{2})$ ionization enthalpies (in $kJ \ mol^{-1}$) and the $(\Delta_{eg} H)$ electron gain enthalpy (in $kJ \ mol^{-1}$) of a few elements are given below:
Elements $\Delta_{i} H_{1}$ $\Delta_{i} H_{2}$ $\Delta_{eg} H$
$I$ $520$ $7300$ $-60$
$II$ $419$ $3051$ $-48$
$III$ $1681$ $3374$ $-328$
$IV$ $1008$ $1846$ $-295$
$V$ $2372$ $5251$ $+48$
$VI$ $738$ $1451$ $-40$

Which of the above elements is likely to be:
$(a)$ the least reactive element.
$(b)$ the most reactive metal.
$(c)$ the most reactive non-metal.
$(d)$ the least reactive non-metal.
$(e)$ the metal which can form a stable binary halide of the formula $MX_{2}$ $(X = \text{halogen})$.
$(f)$ the metal which can form a predominantly stable covalent halide of the formula $MX$ $(X = \text{halogen})$?

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