What is the correct order of basic strength o | vedclass

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(C) The atomic numbers of the given lanthanides are: $Ce = 58$,$Eu = 63$,and $Lu = 71$. As we move across the lanthanide series from $Ce$ to $Lu$,the

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$Lu(OH)_3 < Eu(OH)_3 < Ce(OH)_3$

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(C) The atomic numbers of the given lanthanides are: $Ce = 58$,$Eu = 63$,and $Lu = 71$. As we move across the lanthanide series from $Ce$ to $Lu$,the ionic radius decreases due to lanthanide contraction. This decrease in ionic radius leads to an increase in the covalent character of the $M-OH$ bond according to Fajan's rule. Consequently,the basic strength of the hydroxides decreases as the atomic number increases. Therefore,the correct order of basic strength is $Lu(OH)_3 < Eu(OH)_3 < Ce(OH)_3$.

What is the correct order of basic strength of the following metallic hydroxides?

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