What is the correct sequence of reagents used | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The conversion of nitrobenzene to $m$-dibromobenzene involves the following steps:
$1$. Bromination of nitrobenzene using $Br_2/Fe$ gives $m$-bro

Vedclass · Accepted Answer

$\xrightarrow{Br_2/Fe}$ $\xrightarrow{Sn/HCl}$ $\xrightarrow{NaNO_2/HCl}$ $\xrightarrow{CuBr/HBr}$

Vedclass · Answer

(B) The conversion of nitrobenzene to $m$-dibromobenzene involves the following steps:
$1$. Bromination of nitrobenzene using $Br_2/Fe$ gives $m$-bromonitrobenzene.
$2$. Reduction of $m$-bromonitrobenzene using $Sn/HCl$ gives $m$-bromoaniline.
$3$. Diazotization of $m$-bromoaniline using $NaNO_2/HCl$ at $0-5^{\circ}C$ gives $m$-bromobenzenediazonium chloride.
$4$. Sandmeyer reaction of $m$-bromobenzenediazonium chloride with $CuBr/HBr$ replaces the diazonium group with a bromine atom to yield $m$-dibromobenzene.

What is the correct sequence of reagents used for converting nitrobenzene into $m$-dibromobenzene?

Similar Questions

In the given set of reactions,the $IUPAC$ name of product '$Y$' is:
$2-\text{Bromopropane}$ $\xrightarrow[\text{alc. / heat}]{AgCN} X$ $\xrightarrow{LiAlH_4} Y$

What is the product formed when a primary amine reacts with an acid anhydride?

The reaction of Benzenediazonium chloride with aniline yields a yellow dye. The name of the yellow dye is

Which alkene is obtained as the major product in the given reaction?

Reaction of primary amines with aldehydes yields

Vedclass Test Series

Exam Paper Generator

Online Exam Module