What is the current through an ideal PN- junc | vedclass

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(A) In the given circuit,the $P-$side of the diode is connected to the positive terminal of a $1\,V$ battery,and the $N-$side is connected to the posi

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(A) In the given circuit,the $P-$side of the diode is connected to the positive terminal of a $1\,V$ battery,and the $N-$side is connected to the positive terminal of a $3\,V$ battery through a $100\,\Omega$ resistor.Let the potential at the $P-$side be $V_P = 1\,V$ and the potential at the $N-$side be $V_N = 3\,V$.The potential difference across the diode is $V_{PN} = V_P - V_N = 1\,V - 3\,V = -2\,V$.Since the potential at the $N-$side is higher than the potential at the $P-$side,the diode is in reverse-biased condition.For an ideal diode in reverse bias,the resistance is infinite,and therefore,no current flows through the circuit.Thus,the current $I = 0\,mA$.

What is the current through an ideal $PN-$ junction diode shown in the figure below? (in $mA$)

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