What is the energy (in J atom^{-1}) required | vedclass

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(C) The ionization energy of a hydrogen-like species is given by the formula $E = E_H 	imes Z^2 / n^2$, where $E_H$ is the ionization energy of the h

Vedclass · Accepted Answer

$1.962 	imes 10^{-17}$

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(C) The ionization energy of a hydrogen-like species is given by the formula $E = E_H 	imes Z^2 / n^2$, where $E_H$ is the ionization energy of the hydrogen atom in the ground state $(2.18 	imes 10^{-18} 	ext{ J atom}^{-1})$, $Z$ is the atomic number, and $n$ is the principal quantum number.For the process $Li^{2+}(g) 	o Li^{3+}(g) + e^-$, the electron is removed from the $n=1$ state of the lithium ion $(Li^{2+})$.The atomic number of Lithium $(Li)$ is $Z = 3$.Substituting the values into the formula:$E = 2.18 	imes 10^{-18} 	imes (3)^2 / (1)^2$$E = 2.18 	imes 10^{-18} 	imes 9$$E = 1.962 	imes 10^{-17} 	ext{ J atom}^{-1}$.

What is the energy (in $J$ atom$^{-1}$) required for the following process?
$Li^{2+}(g) \to Li^{3+}(g) + e^-$
(Take the ionization energy for the $H$ atom in the ground state as $2.18 \times 10^{-18}$ $J$ atom$^{-1}$)

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What is the energy (in $J$ atom$^{-1}$) required for the following process?$Li^{2+}(g) \to Li^{3+}(g) + e^-$(Take the ionization energy for the $H$ atom in the ground state as $2.18 \times 10^{-18}$ $J$ atom$^{-1}$)