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(D) Let the nodes be $C$ and $D$ at the bottom junctions. The circuit consists of two resistors $R$ in series with the parallel combination of the rem

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None of these

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(D) Let the nodes be $C$ and $D$ at the bottom junctions. The circuit consists of two resistors $R$ in series with the parallel combination of the remaining three resistors.Specifically,the two resistors $R$ at the bottom are in series,giving $R + R = 2R$.This $2R$ is in parallel with the middle resistor $R$,giving an equivalent resistance $R_p = \frac{(2R \cdot R)}{(2R + R)} = \frac{2R^2}{3R} = \frac{2}{3}R$.Adding the two outer resistors $R$ in series,the total equivalent resistance is $R_{eq} = R + \frac{2}{3}R + R = \frac{8}{3}R$.Given $R = 3\,\Omega$,we have $R_{eq} = \frac{8}{3} 	imes 3 = 8\,\Omega$.Since $8\,\Omega$ is not among the options,the correct choice is $D$.

What is the equivalent resistance between $A$ and $B$ in the figure below if $R = 3\,\Omega$?

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