What is the equivalent weight of H_3PO_3 in t | vedclass

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(C) The oxidation state of $P$ in $H_3PO_3$ is $+3$. In $H_3PO_4$,it is $+5$ (oxidation) and in $PH_3$,it is $-3$ (reduction).Change in oxidation stat

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$\frac{2M}{3}$

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(C) The oxidation state of $P$ in $H_3PO_3$ is $+3$. In $H_3PO_4$,it is $+5$ (oxidation) and in $PH_3$,it is $-3$ (reduction).Change in oxidation state for oxidation: $5 - 3 = 2$.Change in oxidation state for reduction: $3 - (-3) = 6$.For a disproportionation reaction,the equivalent weight is calculated using the formula:$E_w = \frac{M}{n_f}$,where $n_f = \frac{n_1 	imes n_2}{n_1 + n_2}$.Here,$n_1 = 2$ and $n_2 = 6$.$n_f = \frac{2 	imes 6}{2 + 6} = \frac{12}{8} = \frac{3}{2}$.Therefore,$E_w = \frac{M}{3/2} = \frac{2M}{3}$.

What is the equivalent weight of $H_3PO_3$ in the following disproportionation reaction?
$4H_3PO_3 \rightarrow 3H_3PO_4 + PH_3$

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What is the equivalent weight of $H_3PO_3$ in the following disproportionation reaction?$4H_3PO_3 \rightarrow 3H_3PO_4 + PH_3$