What is the final product (major) A in the gi | vedclass

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(A) The reaction of a secondary alcohol with $HCl$ proceeds via an $S_N1$ mechanism involving the formation of a carbocation intermediate.$1$. Protona

Vedclass · Accepted Answer

$1-$ethyl$-2-$methyl$-1-$chlorocyclohexane

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(A) The reaction of a secondary alcohol with $HCl$ proceeds via an $S_N1$ mechanism involving the formation of a carbocation intermediate.$1$. Protonation of the $-OH$ group by $HCl$ converts it into a good leaving group $(-OH_2^+)$.$2$. Loss of water molecule generates a secondary carbocation at the carbon atom attached to the cyclohexane ring.$3$. This secondary carbocation undergoes a $1,2$-hydride shift to form a more stable tertiary carbocation at the ring carbon.$4$. Finally,the nucleophilic chloride ion $(Cl^-)$ attacks the tertiary carbocation to form the major product,$1$-ethyl-$1$-chloro-$2$-methylcyclohexane.

What is the final product (major) $A$ in the given reaction?

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