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(D) The reaction of benzonitrile $(C_6H_5CN)$ with phenyl magnesium bromide $(C_6H_5MgBr)$ in dry ether proceeds via a nucleophilic addition to the ni

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Benzophenone

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(D) The reaction of benzonitrile $(C_6H_5CN)$ with phenyl magnesium bromide $(C_6H_5MgBr)$ in dry ether proceeds via a nucleophilic addition to the nitrile group.$1$. The phenyl group from the Grignard reagent attacks the electrophilic carbon of the nitrile group to form an imine magnesium bromide complex $(C_6H_5-C(C_6H_5)=NMgBr)$.$2$. Upon subsequent acid hydrolysis $(H_3O^+)$,the imine complex is converted into a ketone.$3$. The final product formed is benzophenone $(C_6H_5-CO-C_6H_5)$.

Item-$I$	Item-$II$
$I$. Benzene	$P$. $HCl$ and $SnCl_2, H_3O^{+}$
$II$. Benzonitrile	$Q$. $H_2, Pd-BaSO_4, S$ and quinoline
$III$. Benzoyl Chloride	$R$. $CO, HCl$ and $AlCl_3$

What is the final product obtained when benzonitrile reacts with phenyl magnesium bromide in equimolar proportion?

Similar Questions

In which of the following pairs is the reactant correctly matched with the reagent that would form benzaldehyde as the product?

The major product of the following reaction is:
$CH_3CH_2CH=CH_2$ $\xrightarrow[Rh \ \text{catalyst}]{H_2/CO}$

What are $X$ and $Y$ in the following reactions?

The correct match between Item-$I$ (starting material) and Item-$II$ (reagent) for the preparation of benzaldehyde is :
Item-$I$ Item-$II$
$I$. Benzene $P$. $HCl$ and $SnCl_2, H_3O^{+}$
$II$. Benzonitrile $Q$. $H_2, Pd-BaSO_4, S$ and quinoline
$III$. Benzoyl Chloride $R$. $CO, HCl$ and $AlCl_3$

Which of the following reactions will not give an aldehyde as the major product?

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