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(D) $1$. The ozonolysis of $C_4H_8$ gives acetone $(CH_3COCH_3)$ and formaldehyde $(HCHO)$. This confirms that $C_4H_8$ is isobutylene,$(CH_3)_2C=CH_2

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$3-$methylbutanoic acid

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(D) $1$. The ozonolysis of $C_4H_8$ gives acetone $(CH_3COCH_3)$ and formaldehyde $(HCHO)$. This confirms that $C_4H_8$ is isobutylene,$(CH_3)_2C=CH_2$. $2$. Reaction of isobutylene with $HBr$ in the presence of peroxide follows anti-Markovnikov addition: $(CH_3)_2C=CH_2 + HBr \xrightarrow{	ext{peroxide}} (CH_3)_2CH-CH_2Br$ ($X$ is $1-$bromo$-2-$methylpropane). $3$. $X$ reacts with $Mg$ in dry ether to form the Grignard reagent: $(CH_3)_2CH-CH_2MgBr$. $4$. The Grignard reagent reacts with $CO_2$ followed by acid hydrolysis to form a carboxylic acid: $(CH_3)_2CH-CH_2MgBr + CO_2$ $ightarrow (CH_3)_2CH-CH_2COOMgBr$ $\xrightarrow{H_3O^+} (CH_3)_2CH-CH_2COOH$. $5$. The final product $Y$ is $3-$methylbutanoic acid.

What is the final product of the following reaction sequence?
$C_4H_8$ $\xrightarrow[\text{peroxide}]{\text{HBr}} X$ $\xrightarrow[\text{(ii) } CO_2]{\text{(i) Mg/dry ether, (iii) } H_3O^+} Y$

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What is the final product of the following reaction sequence? $C_4H_8$ $\xrightarrow[\text{peroxide}]{\text{HBr}} X$ $\xrightarrow[\text{(ii) } CO_2]{\text{(i) Mg/dry ether, (iii) } H_3O^+} Y$