What is the heat capacity of copper of $40 \, g$ and specific heat $0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$?

$(12 \, erg (^{\circ} C)^{-1})$ The heat capacity $C$ is defined as the product of the mass $m$ and the specific heat capacity $s$ of the substance.
Given:
Mass $m = 40 \, g$
Specific heat $s = 0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$
Calculation:
$C = m \times s$
$C = 40 \, g \times 0.3 \, erg \, g^{-1} (^{\circ} C)^{-1}$
$C = 12 \, erg (^{\circ} C)^{-1}$