What is the kinetic energy (in $J \ mol^{-1}$) of one mole of an ideal gas (molar mass $= 0.1 \ kg \ mol^{-1}$) if its rms velocity is $4 \times 10^2 \ ms^{-1}$ at $T(K)$?
- A$2 \times 10^5$
- B$8 \times 10^4$
- C$8 \times 10^2$
- D$8 \times 10^3$
Explore More
Similar Questions
At which temperature will the average velocity of ammonia $(NH_3)$ molecules be identical to the average velocity of nitric oxide $(NO)$ molecules at $327\,^oC$?
Medium
View SolutionAt $400 \ K$,the root mean square $(rms)$ speed of a gas $X$ (molecular weight $= 40$) is equal to the most probable speed of gas $Y$ at $60 \ K$. The molecular weight of the gas $Y$ is:
By what ratio does the average velocity of a gas molecule change when the temperature is raised from $50^{\circ}C$ to $200^{\circ}C$ (in $: 1$)?
Medium
View SolutionMolecular velocities of two gases at the same temperature are $v_1$ and $v_2$. Their masses are $m_1$ and $m_2$ respectively. Which of the following expressions is correct?
Medium
View SolutionAt $256 \ K$,the $rms$ speed of $SO_2$ gas molecules is $3.16 \times 10^2 \ ms^{-1}$. What is the most probable velocity (in $ms^{-1}$) of the same gas at the same temperature?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo