What is the loss in molar mass when a primary | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The Hofmann bromamide degradation reaction is represented as: $R-CONH_2 + Br_2 + 4KOH \rightarrow R-NH_2 + K_2CO_3 + 2KBr + 2H_2O$. In this reacti

Vedclass · Accepted Answer

$28 \ g \ mol^{-1}$

Vedclass · Answer

(C) The Hofmann bromamide degradation reaction is represented as: $R-CONH_2 + Br_2 + 4KOH \rightarrow R-NH_2 + K_2CO_3 + 2KBr + 2H_2O$. In this reaction,the amide group $(-CONH_2)$ is converted into an amine group $(-NH_2)$. The carbon atom of the carbonyl group is lost as potassium carbonate $(K_2CO_3)$. The loss in molar mass corresponds to the mass of the carbonyl group $(CO)$ that is removed from the amide to form the amine. The molar mass of $CO$ is $12 + 16 = 28 \ g \ mol^{-1}$. Therefore,the loss in molar mass is $28 \ g \ mol^{-1}$.

What is the loss in molar mass when a primary amine is obtained by Hofmann degradation of amide?

Similar Questions

Hydrolysis of alkyl isocyanide yields:

Arrange the following in decreasing order of their $pK_{b}$ values:

Consider the following:
Statement-$I$: In the nitration of aniline,a significant amount of $m$-nitroaniline is formed.
Statement-$II$: In the presence of a strongly acidic medium,aniline is protonated to form the anilinium ion,which is meta-directing.

Identify the products $y$ and $x$ in the following reaction sequence:
$C_6H_5CONH_2 \xrightarrow{NaOBr} y$
$C_6H_5CONH_2 \xrightarrow[(ii) H_3O^+]{(i) C_6H_5SO_2Cl / py, \Delta} x$

The order of basicity among the following nitrogen compounds is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module