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(D) The cross-aldol condensation between benzene carbaldehyde (benzaldehyde,$C_6H_5CHO$) and $1$-phenyl ethane$-1$-one (acetophenone,$C_6H_5COCH_3$) i

Vedclass · Accepted Answer

$C_6H_5-CH=CH-CO-C_6H_5$

Vedclass · Answer

(D) The cross-aldol condensation between benzene carbaldehyde (benzaldehyde,$C_6H_5CHO$) and $1$-phenyl ethane$-1$-one (acetophenone,$C_6H_5COCH_3$) in the presence of a base leads to the formation of $1,3$-diphenylprop$-2$-en$-1$-one,commonly known as chalcone.The reaction is as follows:$C_6H_5CHO + CH_3COC_6H_5 \xrightarrow{OH^-} C_6H_5CH=CHCOC_6H_5 + H_2O$Here,the enolate ion formed from acetophenone attacks the carbonyl carbon of benzaldehyde,followed by dehydration to form the $\alpha,\beta$-unsaturated ketone,which is represented by option $D$.

What is the main product obtained by the cross-aldol condensation of benzene carbaldehyde and $1$-phenyl ethane$-1$-one?

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