What is the major alkene formed in the follow | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Hofmann elimination of quaternary ammonium salts follows the anti-Zaitsev rule,where the least substituted alkene is formed as the major product d

Vedclass · Accepted Answer

Vedclass · Answer

(D) Hofmann elimination of quaternary ammonium salts follows the anti-Zaitsev rule,where the least substituted alkene is formed as the major product due to steric hindrance.In the given molecule,the nitrogen atom is attached to three different types of $\beta$-hydrogens:$1$. The $\beta$-hydrogens on the methyl groups attached to the nitrogen.$2$. The $\beta$-hydrogen at the $C-2$ position of the ring.$3$. The $\beta$-hydrogen at the $C-6$ position of the ring.Elimination involving the $C-2$ hydrogen leads to the formation of the less substituted alkene (terminal alkene) because the base abstracts the most accessible proton,which is less sterically hindered. Thus,the major product is the one where the double bond is formed at the terminal position relative to the ring,resulting in the formation of $N,N$-dimethylpent$-4-$en$-2-$amine.

What is the major alkene formed in the following Hofmann elimination?

Similar Questions

Product $(B)$ in this reaction is

Which among the following reactions represents the Carbylamine reaction?

The major product in the following reaction sequence is:

Identify the product $A$ in the following reaction:
Aniline $\xrightarrow{(CH_3CO)_2O / \text{pyridine}} A$

Fluorination of an aromatic ring is easily accomplished by treating a diazonium salt with $HBF_4$. Which of the following conditions is correct about this reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module