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(D) The reaction of $1$-methylcyclopentene with $D-Cl$ proceeds via an electrophilic addition mechanism.$1$. The electrophile $D^+$ attacks the double

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Both $(b)$ and $(c)$

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(D) The reaction of $1$-methylcyclopentene with $D-Cl$ proceeds via an electrophilic addition mechanism.$1$. The electrophile $D^+$ attacks the double bond to form the more stable tertiary carbocation at the $C-1$ position.$2$. The resulting carbocation is $sp^2$ hybridized and planar.$3$. The nucleophile $Cl^-$ can attack the planar carbocation from either the top or the bottom face with equal probability.$4$. This leads to the formation of both possible stereoisomers (diastereomers) where the $Cl$ atom and the $CH_3$ group can be either cis or trans to each other relative to the $D$ atom.$5$. Therefore,both products shown in $(b)$ and $(c)$ are formed.

What is the major product expected from the following reaction?
Where $D$ is an isotope of hydrogen.

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What is the major product expected from the following reaction?Where $D$ is an isotope of hydrogen.