What is the major product formed when salicyl | vedclass

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(B) Salicylaldehyde ($2$-hydroxybenzaldehyde) contains a strongly activating $-OH$ group,which directs electrophilic substitution to the ortho and par

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(B) Salicylaldehyde ($2$-hydroxybenzaldehyde) contains a strongly activating $-OH$ group,which directs electrophilic substitution to the ortho and para positions.Since the ortho position is already occupied by the $-CHO$ group,the bromine atoms substitute at the $3$ and $5$ positions (which are ortho and para to the $-OH$ group respectively).When treated with $2$ equivalents of $Br_2$ in glacial acetic acid,the reaction yields $3,5-$dibromosalicylaldehyde as the major product.

What is the major product formed when salicylaldehyde is reacted with $2$ equivalents of bromine in glacial acetic acid at $0^{\circ} C$?

Similar Questions

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