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(A) The reaction is the electrophilic addition of $HX$ to an alkene,which follows Markovnikov's rule. According to Markovnikov's rule,the negative par

Vedclass · Accepted Answer

$CH_3-C(CH_3)(X)-CH_2-CH_3$

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(A) The reaction is the electrophilic addition of $HX$ to an alkene,which follows Markovnikov's rule. According to Markovnikov's rule,the negative part of the addendum $(X^-)$ attaches to the carbon atom of the double bond that has fewer hydrogen atoms. The starting material is $3,3-	ext{dimethylbut-1-ene}$ (or a similar branched alkene structure as shown). Upon protonation of the double bond,a carbocation is formed. The proton $(H^+)$ adds to the terminal $CH_2$ group to form a more stable secondary or tertiary carbocation. In this specific structure,the addition of $H^+$ to the terminal carbon creates a secondary carbocation at the $C-2$ position,which can undergo a hydride or methyl shift to form a more stable tertiary carbocation. However,looking at the options provided,the product formed by direct Markovnikov addition to the double bond is $CH_3-C(CH_3)(X)-CH_2-CH_3$ (where $X$ is at the $C-2$ position). Thus,the major product is $CH_3-C(CH_3)(X)-CH_2-CH_3$.

What is the major product in the following reaction?

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