What is the maximum acceleration of a train s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given,mass of the box $m = 50 \ kg$,coefficient of static friction $\mu = 0.3$,and acceleration due to gravity $g = 10 \ m \ s^{-2}$.When the trai

Vedclass · Accepted Answer

$3.0$

Vedclass · Answer

(B) Given,mass of the box $m = 50 \ kg$,coefficient of static friction $\mu = 0.3$,and acceleration due to gravity $g = 10 \ m \ s^{-2}$.When the train accelerates with acceleration $a$,a pseudo force $F_p = ma$ acts on the box in the direction opposite to the acceleration of the train.For the box to remain stationary on the floor of the train,the frictional force $f$ must balance this pseudo force.The maximum frictional force (limiting friction) is given by $f_{max} = \mu N$,where $N = mg$ is the normal reaction.Thus,for the box to remain stationary,we must have $ma \leq \mu mg$.The maximum acceleration $a_{max}$ is given by $a_{max} = \mu g$.Substituting the values,$a_{max} = 0.3 	imes 10 = 3.0 \ m \ s^{-2}$.Therefore,the maximum acceleration of the train is $3.0 \ m \ s^{-2}$.

What is the maximum acceleration of a train such that a $50 \ kg$ box lying on its floor remains stationary (in $m \ s^{-2}$)? (Given: Coefficient of static friction between the box and the train's floor is $0.3$ and $g = 10 \ m \ s^{-2}$)

Similar Questions

$A$ body of mass $m$ rests on a horizontal surface. The coefficient of friction between the body and the surface is $\mu$. If the mass is pulled by a force $P$ at an angle of $30^{\circ}$ with the horizontal as shown in the figure,the limiting friction between the body and the surface will be:

$A$ force of $98 \, N$ is required to just start moving a body of mass $100 \, kg$ over ice. The coefficient of static friction is

The blocks $A$ and $B$ are arranged as shown in the figure. The pulley is frictionless. The mass of $A$ is $10 \, kg$. The coefficient of friction of $A$ with the horizontal surface is $0.20$. The minimum mass of $B$ to start the motion will be...... $kg$.

$A$ body of mass $m$ is kept on a rough horizontal surface (coefficient of friction $= \mu$). $A$ horizontal force is applied on the body,but it does not move. The resultant of the normal reaction and the frictional force acting on the object is given by $F$,where $F$ is:

To avoid slipping while walking on ice,one should take smaller steps because of the

Vedclass Test Series

Exam Paper Generator

Online Exam Module