What is the mole fraction of the solute in 2. | vedclass

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(A) $2.5 \ m$ aqueous solution means $2.5 \ mol$ of solute is present in $1 \ kg$ $(1000 \ g)$ of solvent $(water)$.$	ext{Moles of solute} = 2.5 \ mo

Vedclass · Accepted Answer

$0.043$

Vedclass · Answer

(A) $2.5 \ m$ aqueous solution means $2.5 \ mol$ of solute is present in $1 \ kg$ $(1000 \ g)$ of solvent $(water)$.$	ext{Moles of solute} = 2.5 \ mol$$	ext{Moles of water} = \frac{1000 \ g}{18 \ g/mol} \approx 55.56 \ mol$$	ext{Mole fraction of solute} (\chi_{solute}) = \frac{n_{solute}}{n_{solute} + n_{solvent}}$$\chi_{solute} = \frac{2.5}{2.5 + 55.56} = \frac{2.5}{58.06} \approx 0.043$

What is the mole fraction of the solute in $2.5 \ m$ aqueous solution?

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