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(B) The total number of electrons in an $F_2$ molecule is $18$ $(9 + 9)$.The molecular orbital configuration for $F_2$ is: $\sigma 1s^2, \sigma^* 1s^2

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$10$ and $8$

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(B) The total number of electrons in an $F_2$ molecule is $18$ $(9 + 9)$.The molecular orbital configuration for $F_2$ is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$.Counting the electrons in bonding molecular orbitals (those without an asterisk): $2 (\sigma 1s) + 2 (\sigma 2s) + 2 (\sigma 2p_z) + 4 (\pi 2p_x, \pi 2p_y) = 10$.Counting the electrons in antibonding molecular orbitals (those with an asterisk): $2 (\sigma^* 1s) + 2 (\sigma^* 2s) + 4 (\pi^* 2p_x, \pi^* 2p_y) = 8$.Therefore,the number of electrons in bonding and antibonding molecular orbitals are $10$ and $8$ respectively.

What is the number of electrons in bonding molecular orbitals and antibonding molecular orbitals respectively in $F_2$ molecule?

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