Easy
What is the number of electrons present in the $3d$ orbital of $Ti$ in the $+2$ oxidation state?
- AZero
- BOne
- CTwo
- DThree
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Which of the following sets of quantum numbers represents the orbital with the highest energy?
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View SolutionThe correct order of decreasing energy for the electrons whose quantum numbers $n$ and $l$ are given below, is
$A$. $n=5, l=2$
$B$. $n=5, l=0$
$C$. $n=4, l=3$
$D$. $n=4, l=1$
$A$. $n=5, l=2$
$B$. $n=5, l=0$
$C$. $n=4, l=3$
$D$. $n=4, l=1$
The rule which states that an electron enters the sub-shell for which the $(n + l)$ value is minimum is known as:
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