What is the number of tetrahedral voids present in $0.5 \text{ mole}$ of a compound forming an $hcp$ structure?
- A$1.223 \times 10^{23}$
- B$3.628 \times 10^{23}$
- C$4.487 \times 10^{23}$
- D$6.022 \times 10^{23}$
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$A$ compound is formed by two elements $X$ and $Y$. The element $Y$ forms a cubic close-packed $(CCP)$ arrangement and the atoms of element $X$ occupy one-third of the tetrahedral voids. What is the formula of the compound?
The number of tetrahedral voids present in $0.5 \ mole$ of $hcp$ crystal structure is:
In a hexagonal close-packed $(HCP)$ structure,the third layer covers the ........ holes created between the first and second layers.
Easy
View SolutionCalculate the packing efficiency in a simple cubic unit cell.
Difficult
View SolutionCalculate the total number of tetrahedral and octahedral voids formed in $0.6 \ mol$ of a compound if it forms $hcp$ structure.
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