What is the number of unpaired electron(s) in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $N_2$ $(14 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^2$. $HOMO$ is $\sigma 2p_z$,whic

Vedclass · Accepted Answer

$0, 1, 2, 1$

Vedclass · Answer

(A) $N_2$ $(14 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^2$. $HOMO$ is $\sigma 2p_z$,which has $0$ unpaired electrons.$N_2^{+}$ $(13 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^1$. $HOMO$ is $\sigma 2p_z$,which has $1$ unpaired electron.$O_2$ $(16 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. $HOMO$ is $\pi^* 2p$,which has $2$ unpaired electrons.$O_2^{+}$ $(15 \ e^-)$: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$. $HOMO$ is $\pi^* 2p$,which has $1$ unpaired electron.Thus,the number of unpaired electrons is $0, 1, 2, 1$ respectively.

List-$I$	List-$II$
$A$. $\Psi_{MO} = \Psi_{A} - \Psi_{B}$	$I$. Dipole moment
$B$. $\mu = Q \times r$	$II$. Bonding molecular orbital
$C$. $\frac{N_{b} - N_{a}}{2}$	$III$. Anti-bonding molecular orbital
$D$. $\Psi_{MO} = \Psi_{A} + \Psi_{B}$	$IV$. Bond order

What is the number of unpaired electron$(s)$ in the highest occupied molecular orbital $(HOMO)$ of the following species: $N_2$,$N_2^{+}$,$O_2$,$O_2^{+}$?

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A$. $\Psi_{MO} = \Psi_{A} - \Psi_{B}$ $I$. Dipole moment

$B$. $\mu = Q \times r$ $II$. Bonding molecular orbital

$C$. $\frac{N_{b} - N_{a}}{2}$ $III$. Anti-bonding molecular orbital

$D$. $\Psi_{MO} = \Psi_{A} + \Psi_{B}$ $IV$. Bond order

In the conversion of $N_2$ into $N_2^+$,the electron will be lost from which of the following molecular orbitals?

Arrange the following species in the decreasing order of their bond orders:
$(I)$ $NO$
$(II)$ $NO^+$
$(III)$ $NO^-$

Incorrect statement regarding $N(SiH_3)_3$ is

Among the following molecules / ions $C_2^{2-}, N_2^{2-}, O_2^{2-}, O_2$,which one is diamagnetic and has the shortest bond length?

Vedclass Test Series

Exam Paper Generator

Online Exam Module