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(D) The atomic number of $Sc$ is $21$. The electronic configuration of $Sc$ is $[Ar] \ 3d^1 \ 4s^2$. Thus,$Sc^{3+}$ is $[Ar]$,which has $0$ unpaired e

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$0, 0$

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(D) The atomic number of $Sc$ is $21$. The electronic configuration of $Sc$ is $[Ar] \ 3d^1 \ 4s^2$. Thus,$Sc^{3+}$ is $[Ar]$,which has $0$ unpaired electrons.The atomic number of $Zn$ is $30$. The electronic configuration of $Zn$ is $[Ar] \ 3d^{10} \ 4s^2$. Thus,$Zn^{2+}$ is $[Ar] \ 3d^{10}$,which has $0$ unpaired electrons.Therefore,the number of unpaired electrons in $Sc^{3+}$ and $Zn^{2+}$ are $0$ and $0$ respectively.

What is the number of unpaired electrons present in $Sc^{3+}$ and $Zn^{2+}$ ions respectively?

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