What is the oxidation number of S in H_2S_2O_ | vedclass

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(D) The structure of $H_2S_2O_8$ (peroxodisulphuric acid) contains a peroxide linkage $(-O-O-)$. In this structure,there are two sulphur atoms,two hyd

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$+6$

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(D) The structure of $H_2S_2O_8$ (peroxodisulphuric acid) contains a peroxide linkage $(-O-O-)$. In this structure,there are two sulphur atoms,two hydroxyl groups $(-OH)$,two peroxide oxygen atoms (oxidation state $-1$ each),and six terminal oxygen atoms (oxidation state $-2$ each). Let the oxidation state of sulphur be $x$. The sum of oxidation states in a neutral molecule is zero: $2(+1) + 2(x) + 2(-1) + 6(-2) = 0$ $2 + 2x - 2 - 12 = 0$ $2x - 12 = 0$ $2x = 12$ $x = +6$ Thus,the oxidation state of $S$ in $H_2S_2O_8$ is $+6$.

What is the oxidation number of $S$ in $H_2S_2O_8$?

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