What is the oxidation state of xenon in xenon | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The chemical formula for xenon monooxytetrafluoride is $XeOF_4$. Let the oxidation state of xenon be $x$. The oxidation state of oxygen is $-2$ an

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The chemical formula for xenon monooxytetrafluoride is $XeOF_4$. Let the oxidation state of xenon be $x$. The oxidation state of oxygen is $-2$ and the oxidation state of fluorine is $-1$. Setting the sum of oxidation states equal to the charge of the molecule $(0)$: $x + (-2) + 4(-1) = 0$ $x - 2 - 4 = 0$ $x - 6 = 0$ $x = +6$. Therefore,the oxidation state of xenon in $XeOF_4$ is $+6$.

What is the oxidation state of xenon in xenon monooxytetrafluoride?

Similar Questions

The number of peroxide bonds in the perxenate ion $[XeO_6]^{4-}$ is ........

Which of the following Xenon compounds does not produce explosive $XeO_3$ on its complete hydrolysis?

Which one of the following noble gases is not found in the atmosphere?

The melting and boiling points of noble gases are ...

Select the $INCORRECT$ statement regarding the following reactions:
$XeF_6 + \text{excess } H_2O \rightarrow 'X' + HF$
$XeF_6 + 2 \text{ moles } H_2O \rightarrow 'Y' + HF$

Vedclass Test Series

Exam Paper Generator

Online Exam Module