What is the position of elements La (Z=57) an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The element $La (Z=57)$ has the electronic configuration $[Xe] 5d^1 6s^2$. It belongs to Group-$3$ and Period-$6$. $Ce (Z=58)$ is the first elemen

Vedclass · Accepted Answer

$La = 	ext{Group-}3, 	ext{Period-}6; Ce = 	ext{Group-}3, 	ext{Period-}6$

Vedclass · Answer

(A) The element $La (Z=57)$ has the electronic configuration $[Xe] 5d^1 6s^2$. It belongs to Group-$3$ and Period-$6$. $Ce (Z=58)$ is the first element of the lanthanoid series with the configuration $[Xe] 4f^1 5d^1 6s^2$. In the long form of the periodic table,all lanthanoids (from $Z=57$ to $71$) are placed in Group-$3$ and Period-$6$ to avoid disrupting the table structure. Therefore,both $La$ and $Ce$ belong to Group-$3$ and Period-$6$.

List-$I$	List-$II$
$A$. (Atomic number,$Z = 112$)	$I$. $s$
$B$. (Atomic number,$Z = 116$)	$II$. $p$
$C$. (Atomic number,$Z = 88$)	$III$. $d$
$D$. (Atomic number,$Z = 100$)	$IV$. $f$

What is the position of elements $La (Z=57)$ and $Ce (Z=58)$ respectively in the long form of the periodic table?

Similar Questions

Match the following:
List-$I$ List-$II$
$A$. (Atomic number,$Z = 112$) $I$. $s$
$B$. (Atomic number,$Z = 116$) $II$. $p$
$C$. (Atomic number,$Z = 88$) $III$. $d$
$D$. (Atomic number,$Z = 100$) $IV$. $f$

Which of the following statements is incorrect?

In the modern periodic table,which groups of elements are known as $d$-block elements?

The element with outer electronic configuration $(n-1)d^2 ns^2$,where $n=4$,would belong to

Prove that according to quantum numbers,the $6^{th}$ period contains $32$ elements.

Vedclass Test Series

Exam Paper Generator

Online Exam Module