What is the product Z in the following reacti | vedclass

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(B) $1$. The first step is the Sandmeyer reaction where benzene diazonium chloride $(C_6H_5N_2Cl)$ reacts with $Cu_2Cl_2/HCl$ to form chlorobenzene $(

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$p$-Chlorotoluene

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(B) $1$. The first step is the Sandmeyer reaction where benzene diazonium chloride $(C_6H_5N_2Cl)$ reacts with $Cu_2Cl_2/HCl$ to form chlorobenzene $(X = C_6H_5Cl)$.$2$. The second step is the Wurtz-Fittig reaction where chlorobenzene reacts with methyl chloride $(CH_3Cl)$ and sodium $(Na)$ in dry ether to form toluene $(Y = C_6H_5CH_3)$.$3$. The third step is electrophilic aromatic substitution (chlorination) of toluene using $Cl_2$ in the presence of $Fe$ (a Lewis acid catalyst) in the dark. Since the methyl group $(-CH_3)$ is ortho/para directing,the major product formed is $p$-chlorotoluene $(Z = p-Cl-C_6H_4-CH_3)$.

What is the product $Z$ in the following reaction sequence?
$C_6H_5N_2Cl$ $\xrightarrow{Cu_2Cl_2/HCl} X$ $\xrightarrow{CH_3Cl/Na, \text{dry ether}} Y$ $\xrightarrow{Cl_2/Fe, \text{dark}} Z$

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What is the product $X$ in the following Wurtz-Fittig reaction?

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What is the product $Z$ in the following reaction sequence?$C_6H_5N_2Cl$ $\xrightarrow{Cu_2Cl_2/HCl} X$ $\xrightarrow{CH_3Cl/Na, \text{dry ether}} Y$ $\xrightarrow{Cl_2/Fe, \text{dark}} Z$