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(C) The peroxide effect (Kharasch effect) is only observed with $HBr$ due to the favorable energetics of the free radical mechanism. $HCl$ has a stron

Vedclass · Accepted Answer

Anti-Markovnikov addition for $HBr$ only

Vedclass · Answer

(C) The peroxide effect (Kharasch effect) is only observed with $HBr$ due to the favorable energetics of the free radical mechanism. $HCl$ has a strong $H-Cl$ bond,making the initiation step endothermic. $HI$ forms $I$ radicals that readily combine to form $I_2$ rather than adding to the double bond. Therefore,only $HBr$ shows Anti-Markovnikov addition in the presence of peroxide.

What is the product obtained from the reaction of $HCl$,$HBr$,and $HI$ with alkenes in the presence of peroxide?

Similar Questions

Predict the product$(s)$ obtained for the following reaction:
$3$-methylcyclopentene + $Br_2 / CCl_4 \rightarrow ?$

$(CH_3)_2C=C(CH_3)_2 \xrightarrow{\text{Catalyst}, H_2} \text{Number of optical isomers in the product?}$

What is the product formed when $CH_3-CH=CH_2$ is treated with $B_2H_6$ followed by the action of $H_2O_2$?

Which of the products will be the major product in the reaction given below?
$CH_3CH=CH_2 + HI \to CH_3CH_2CH_2I_{(A)} + CH_3CHICH_{3(B)}$

The reaction shown below is an example of:
$Cyclohexene + Br_2 \rightarrow 1,2-dibromocyclohexane$

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