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(D) The reaction between a carboxylic acid and an alcohol in the presence of an acid catalyst $(H^+)$ is known as Fischer esterification. In this mech

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(D) The reaction between a carboxylic acid and an alcohol in the presence of an acid catalyst $(H^+)$ is known as Fischer esterification. In this mechanism,the bond cleavage occurs between the $C-OH$ bond of the carboxylic acid and the $O-H$ bond of the alcohol. Specifically,the $-OH$ group of the carboxylic acid is removed,and the $-OCH_3$ group from the alcohol replaces it. Therefore,the oxygen atom labeled with $^{18}O$ from the methanol $(CH_3^{18}OH)$ will be incorporated into the ester product,while the water molecule formed will contain the oxygen from the carboxylic acid. The reaction is: $C_6H_5COOH + CH_3^{18}OH \xrightarrow{H^+} C_6H_5CO^{18}OCH_3 + H_2O$.

What is the product obtained from the following reaction?

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