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(A) The reaction of acetaldehyde $(CH_3CHO)$ with semicarbazide $(H_2N-NH-CO-NH_2)$ is a nucleophilic addition-elimination reaction.In this reaction,t

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$H_3C-CH=N-NH-CO-NH_2$

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(A) The reaction of acetaldehyde $(CH_3CHO)$ with semicarbazide $(H_2N-NH-CO-NH_2)$ is a nucleophilic addition-elimination reaction.In this reaction,the carbonyl oxygen of the aldehyde is replaced by the nitrogen of the semicarbazide,resulting in the formation of a semicarbazone.The reaction is as follows:$CH_3CHO + H_2N-NH-CO-NH_2 \rightarrow CH_3CH=N-NH-CO-NH_2 + H_2O$The product formed is acetaldehyde semicarbazone,which corresponds to the structure $H_3C-CH=N-NH-CO-NH_2$.

$I. HNO_3$	$II. NH_2NH_2 / OH^-$
$III. 2[Ag(NH_3)_2]^+$	$IV. NaOH$

What is the product obtained in the reaction of acetaldehyde with semicarbazide?

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