What is the proportion of $s$-character in $sp^3$,$sp^2$,and $sp$ hybrid orbitals? What is the order of electronegativity in it?

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(N/A) The $s$-character in hybrid orbitals is calculated as follows:
$sp^3$: $1/4 = 25 \%$,$sp^2$: $1/3 = 33.3 \%$,$sp$: $1/2 = 50 \%$.
Electronegativity is directly proportional to the $s$-character because $s$-orbitals are closer to the nucleus.
Therefore,the order of electronegativity is $sp > sp^2 > sp^3$.
Hybrid Orbital $s$-character
$sp^3$ $25 \%$
$sp^2$ $33.3 \%$
$sp$ $50 \%$

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