What is the quantity of sugar charcoal obtain | vedclass

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Question

(B) The dehydration reaction of sugar $(C_{12}H_{22}O_{11})$ by concentrated sulphuric acid is given by: $C_{12}H_{22}O_{11} \rightarrow 12C + 11H_2O$

Vedclass · Accepted Answer

$14.4$

Vedclass · Answer

(B) The dehydration reaction of sugar $(C_{12}H_{22}O_{11})$ by concentrated sulphuric acid is given by: $C_{12}H_{22}O_{11} ightarrow 12C + 11H_2O$ The molar mass of sugar $(C_{12}H_{22}O_{11})$ is $12 	imes 12 + 22 	imes 1 + 11 	imes 16 = 144 + 22 + 176 = 342 \ g/mol$. Number of moles of sugar = $\frac{34.2 \ g}{342 \ g/mol} = 0.1 \ mol$. From the stoichiometry of the reaction,$1 \ mol$ of sugar produces $12 \ mol$ of carbon (sugar charcoal). Therefore,$0.1 \ mol$ of sugar produces $0.1 	imes 12 = 1.2 \ mol$ of carbon. Mass of charcoal = $1.2 \ mol 	imes 12 \ g/mol = 14.4 \ g$.

What is the quantity of sugar charcoal obtained when $34.2 \ g$ of sugar is charred using the required quantity of concentrated sulphuric acid under ideal conditions (in $g$)?

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