What is the shape of the BrF_5 molecule? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The central atom $Br$ has $7$ valence electrons. In $BrF_5$,it forms $5$ bonds with $F$ atoms and has $1$ lone pair of electrons.Total electron pa

Vedclass · Accepted Answer

Square pyramidal

Vedclass · Answer

(C) The central atom $Br$ has $7$ valence electrons. In $BrF_5$,it forms $5$ bonds with $F$ atoms and has $1$ lone pair of electrons.Total electron pairs = $5$ (bond pairs) + $1$ (lone pair) = $6$.This corresponds to $sp^3d^2$ hybridization with octahedral electron geometry.Due to the presence of one lone pair,the shape of the $BrF_5$ molecule is square pyramidal.

What is the shape of the $BrF_5$ molecule?

Similar Questions

What is the bond angle $O-S-O$ in the $SO_2$ molecule (in $^{\circ}$)?

Which of the following statements is applicable to $ClF_3$?

Which of the following is planar?

Which of the following molecules is non-linear?

$SF_4$ is isostructural with:

Vedclass Test Series

Exam Paper Generator

Online Exam Module