What is the state of hybridisation of carbon | vedclass

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(A) The state of hybridisation of carbon is determined by the number of sigma bonds and lone pairs around the carbon atom.$(a)$ In $CO_3^{2-}$,the car

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$sp^2, sp^3, sp^2$

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(A) The state of hybridisation of carbon is determined by the number of sigma bonds and lone pairs around the carbon atom.$(a)$ In $CO_3^{2-}$,the carbon atom is bonded to three oxygen atoms with one double bond and two single bonds (resonance hybrid). It has $3$ sigma bonds and $0$ lone pairs,resulting in $sp^2$ hybridisation.$(b)$ In diamond,each carbon atom is bonded to four other carbon atoms via single covalent bonds. It has $4$ sigma bonds and $0$ lone pairs,resulting in $sp^3$ hybridisation.$(c)$ In graphite,each carbon atom is bonded to three other carbon atoms in a hexagonal planar layer. It has $3$ sigma bonds and $0$ lone pairs,resulting in $sp^2$ hybridisation.

What is the state of hybridisation of carbon in $(a)$ $CO_3^{2-}$,$(b)$ diamond,and $(c)$ graphite?

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