What is the structure of $BeCl_2$ molecule in gaseous and solid state?
(N/A) In the solid state,$BeCl_2$ has a polymeric chain-like structure. Each $Be$ atom is surrounded by four $Cl$ atoms,where two $Cl$ atoms are bonded through covalent bonds and the other two are bonded through coordinate bonds. This is shown in structure $A$.
In the gaseous state,beryllium chloride exists as a dimer $(Be_2Cl_4)$ at lower temperatures,which has a bridged structure. At high temperatures (about $1200 \ K$),it dissociates into a monomer $(BeCl_2)$,which is linear in structure. This is shown in structure $B$.
In the gaseous state,beryllium chloride exists as a dimer $(Be_2Cl_4)$ at lower temperatures,which has a bridged structure. At high temperatures (about $1200 \ K$),it dissociates into a monomer $(BeCl_2)$,which is linear in structure. This is shown in structure $B$.
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Similar Questions
In the given compound,the number of sigma $(\sigma)$ and pi $(\pi)$ bonds are respectively:
Medium
View SolutionMatch List-$I$ with List-$II$:
List-$I$ List-$II$ $(P). \ IF_7$ $(a). \ \text{Planar} \ \& \ \text{Polar}$ $(Q). \ SO_2$ $(b). \ \text{Non-planar} \ \& \ \text{Polar}$ $(R). \ SF_4$ $(c). \ \text{Planar} \ \& \ \text{Non-polar}$ $(S). \ CS_2$ $(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$
| List-$I$ | List-$II$ |
|---|---|
| $(P). \ IF_7$ | $(a). \ \text{Planar} \ \& \ \text{Polar}$ |
| $(Q). \ SO_2$ | $(b). \ \text{Non-planar} \ \& \ \text{Polar}$ |
| $(R). \ SF_4$ | $(c). \ \text{Planar} \ \& \ \text{Non-polar}$ |
| $(S). \ CS_2$ | $(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$ |
Medium
View SolutionIdentify the correct thermal stability orders among the following:
$(a) BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4 < BaSO_4$
$(b) HF > H_2O > NH_3 > CH_4$
$(c) NH_3 > PH_3 > AsH_3 > SbH_3$
$(d) LiCl > BeCl_2 > BCl_3 > CCl_4$
$(e) Na_2CO_3 > MgCO_3 > Al_2(CO_3)_3$
$(f) Li_2CO_3 < Na_2CO_3 < K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$
$(a) BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4 < BaSO_4$
$(b) HF > H_2O > NH_3 > CH_4$
$(c) NH_3 > PH_3 > AsH_3 > SbH_3$
$(d) LiCl > BeCl_2 > BCl_3 > CCl_4$
$(e) Na_2CO_3 > MgCO_3 > Al_2(CO_3)_3$
$(f) Li_2CO_3 < Na_2CO_3 < K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$
Which of the following is a Lewis acid?
Easy
View Solution$O_2^{2-}$ is the symbol of which ion?
Easy
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