What is the total number of donor atoms prese | vedclass

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(B) The chemical formula for the Tetracyanonickelate$(II)$ ion is $[Ni(CN)_4]^{2-}$.In this complex,the ligand is the cyanide ion $(CN^-)$.Each cyanid

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$4$

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(B) The chemical formula for the Tetracyanonickelate$(II)$ ion is $[Ni(CN)_4]^{2-}$.In this complex,the ligand is the cyanide ion $(CN^-)$.Each cyanide ion acts as a monodentate ligand,meaning it donates one electron pair through the carbon atom.Since there are $4$ cyanide ligands,the total number of donor atoms is $4 	imes 1 = 4$.

What is the total number of donor atoms present in the Tetracyanonickelate$(II)$ ion?

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