(C) The electronic configuration of $O_2$ molecule is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2

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(C) The electronic configuration of $O_2$ molecule is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1 (\pi^* 2p_y)^1$. Bonding molecular orbitals are those without an asterisk $(*)$. These are $(\sigma 1s)^2$,$(\sigma 2s)^2$,$(\sigma 2p_z)^2$,$(\pi 2p_x)^2$,and $(\pi 2p_y)^2$. Total number of electrons in bonding orbitals = $2 + 2 + 2 + 2 + 2 = 10$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Molecular orbital theory

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What is the total number of electrons present in bonding orbitals of $O_2$ molecule according to molecular orbital theory?

MHT CET 2024 All MHT CET

A
$16$
B
$06$
C
$10$
D
$04$

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Chemical Bonding and Molecular Structure

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Molecular orbital theory

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What is the total number of electrons present in bonding orbitals of $O_2$ molecule according to molecular orbital theory?

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If $N_x$ is the number of bonding orbitals of an atom and $N_y$ is the number of antibonding orbitals,then the molecule/atom will be stable if

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Correct decreasing order of bond order of oxygen species in $I$ to $IV$:
$(I)$ $Na_2O_2$
$(II)$ $O_2[AsF_6]$
$(III)$ $CsO_2$
$(IV)$ $O_2$