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(C) The given reaction is: $x CuO + y NH_3 \rightarrow x Cu + N_2 + x H_2 O$.Step $1$: Balance the atoms other than $O$ and $H$. Since $x$ is the coef

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$x = 3, y = 2$

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(C) The given reaction is: $x CuO + y NH_3 \rightarrow x Cu + N_2 + x H_2 O$.Step $1$: Balance the atoms other than $O$ and $H$. Since $x$ is the coefficient for $CuO$ and $Cu$,the $Cu$ atoms are balanced.Step $2$: Balance $N$ atoms. There are $2$ nitrogen atoms in $N_2$,so we need $2$ $NH_3$ molecules to provide $2$ $N$ atoms. Thus,$y = 2$.Step $3$: Balance $O$ atoms. There are $x$ oxygen atoms in $x CuO$,so we need $x$ $H_2 O$ molecules. This matches the equation.Step $4$: Balance $H$ atoms. There are $3y$ hydrogen atoms in $y NH_3$ and $2x$ hydrogen atoms in $x H_2 O$. Therefore,$3y = 2x$.Step $5$: Substitute $y = 2$ into the equation $3y = 2x$: $3(2) = 2x$ $\Rightarrow 6 = 2x$ $\Rightarrow x = 3$.Thus,$x = 3$ and $y = 2$. The balanced equation is $3 CuO + 2 NH_3 \rightarrow 3 Cu + N_2 + 3 H_2 O$.

What is the value of $x$ and $y$ in order to balance the following redox reaction?
$x CuO + y NH_3 \longrightarrow x Cu + N_2 + x H_2 O$

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What is the value of $x$ and $y$ in order to balance the following redox reaction?$x CuO + y NH_3 \longrightarrow x Cu + N_2 + x H_2 O$