What is the value of shunt resistance require | vedclass

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(A) Given: Resistance of galvanometer $ G = 100 \Omega $; Range of ammeter $ I = 1 	ext{ A} $; Full scale deflection current $ I_{g} = 5 	ext{ mA} =

Vedclass · Accepted Answer

$ \frac{5}{9.95} \Omega $

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(A) Given: Resistance of galvanometer $ G = 100 \Omega $; Range of ammeter $ I = 1 	ext{ A} $; Full scale deflection current $ I_{g} = 5 	ext{ mA} = 5 	imes 10^{-3} 	ext{ A} $.To convert a galvanometer into an ammeter,a shunt resistance $ S $ is connected in parallel with it.The formula for shunt resistance is $ S = \frac{I_{g} G}{I - I_{g}} $.Substituting the given values:$ S = \frac{5 	imes 10^{-3} 	imes 100}{1 - 5 	imes 10^{-3}} $$ S = \frac{0.5}{1 - 0.005} $$ S = \frac{0.5}{0.995} \Omega $$ S = \frac{500}{995} \Omega = \frac{100}{199} \Omega $.Wait,calculating $ \frac{0.5}{0.995} $ gives $ \frac{500}{995} = \frac{100}{199} \approx 0.5025 \Omega $. Checking the options provided,$ \frac{5}{9.95} = \frac{500}{995} = \frac{100}{199} $. Thus,option $ A $ is correct.

What is the value of shunt resistance required to convert a galvanometer of resistance $ 100 \Omega $ into an ammeter of range $ 1 \text{ A} $? Given: Full scale deflection of the galvanometer is $ 5 \text{ mA} $.

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