What is the value of the rate constant for a | vedclass

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(D) The correct option is $(D)$.For a first-order reaction,the rate constant $k$ is given by the formula:$k = \frac{2.303}{t} \log_{10} \frac{[A]_0}{[

Vedclass · Accepted Answer

$1.48 	imes 10^{-2} \ min^{-1}$

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(D) The correct option is $(D)$.For a first-order reaction,the rate constant $k$ is given by the formula:$k = \frac{2.303}{t} \log_{10} \frac{[A]_0}{[A]_t}$Given:Initial concentration $[A]_0 = 100$Amount consumed $= 20 \%$,so remaining concentration $[A]_t = 100 - 20 = 80$Time $t = 15 \ min$Substituting the values:$k = \frac{2.303}{15} \log_{10} \frac{100}{80}$$k = \frac{2.303}{15} \log_{10} (1.25)$$k = \frac{2.303}{15} 	imes 0.0969$$k \approx 0.01487 \ min^{-1} = 1.487 	imes 10^{-2} \ min^{-1}$Thus,the value is approximately $1.48 	imes 10^{-2} \ min^{-1}$.

Time	$t$	$\infty$
$P_{\text{system}}$	$P_t$	$P_{\infty}$

What is the value of the rate constant for a first-order reaction,if it takes $15 \ min$ for the consumption of $20 \%$ of the reactants?

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