(A) According to the Freundlich adsorption isotherm equation: $\log \frac{x}{m} = \log K + \frac{1}{n} \log C$. Comparing this with the equation of a

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(A) According to the Freundlich adsorption isotherm equation: $\log \frac{x}{m} = \log K + \frac{1}{n} \log C$. Comparing this with the equation of a straight line $y = mx + c$,where $y = \log \frac{x}{m}$,$x = \log C$,and $c = \log K$. The slope of the straight line is $\frac{1}{n}$.

Class 12 Chemistry Surface Chemistry Adsorption and Adsorption isotherm

Easy

What is the value of the slope in the Freundlich adsorption isotherm plot of $\log \frac{x}{m}$ against $\log C$?

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A
$\frac{1}{n}$
B
$n$
C
$K$
D
$\log K$

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Class 12 Questions

Class 12

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Surface Chemistry

Subtopic

Adsorption and Adsorption isotherm

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Charcoal is mixed in $500 \ mL$ of $0.5 \ M$ acetic acid solution. After some time,the concentration of the solution becomes $0.3 \ M$. Find the total number of molecules adsorbed on the surface of the charcoal.

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$A$ solid acts as an adsorbent because it has

Easy

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Give an explanation of the applications of adsorption.

Difficult

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Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A$. Physisorption $I$. Single layer adsorption

$B$. Chemisorption $II$. $20-40 \, kJ \, mol^{-1}$

$C$. $N_{2(g)} + 3H_{2(g)} \xrightarrow{Fe(s)} 2NH_{3(g)}$ $III$. Chromatography

$D$. Analytical Application of Adsorption $IV$. Heterogeneous catalysis

Choose the correct answer from the options given below:

List-$I$	List-$II$
$A$. Physisorption	$I$. Single layer adsorption
$B$. Chemisorption	$II$. $20-40 \, kJ \, mol^{-1}$
$C$. $N_{2(g)} + 3H_{2(g)} \xrightarrow{Fe(s)} 2NH_{3(g)}$	$III$. Chromatography
$D$. Analytical Application of Adsorption	$IV$. Heterogeneous catalysis