What may be the first ionisation energy of Na | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the Bohr model,the energy of an electron in an orbit is given by $E_n = -13.6 	imes \frac{Z_{eff}^2}{n^2} \, eV$. For $Na$ $(Z=11)$,

Vedclass · Accepted Answer

$5.1$

Vedclass · Answer

(D) According to the Bohr model,the energy of an electron in an orbit is given by $E_n = -13.6 	imes \frac{Z_{eff}^2}{n^2} \, eV$. For $Na$ $(Z=11)$,the valence electron is in the $3s$ orbital,so $n=3$. The ionisation energy $(I.E.)$ is the energy required to remove the electron from $n=3$ to $n=\infty$,which is equal to the magnitude of the energy of the $n=3$ state. $I.E. = 13.6 	imes \frac{Z_{eff}^2}{n^2} \, eV$. Given $Z_{eff} = 1.84$ and $n = 3$: $I.E. = 13.6 	imes \frac{(1.84)^2}{3^2} = 13.6 	imes \frac{3.3856}{9} \approx 5.11 \, eV$.

What may be the first ionisation energy of $Na$ if it has an effective nuclear charge of $1.84$,assuming the Bohr model of the $H$-atom is effective on it? (in $eV$)

Similar Questions

Which of the following represents the correct order of first ionization enthalpy?
$(i) \ Li < B < Be < C$ $(ii) \ O < N < F$ $(iii) \ Be < N < Ne$

Generally,the first ionization energy increases along a period. But there are some exceptions. One which is not an exception is

What is the order of first,second,and third ionisation enthalpy? Why?

The first ionization enthalpies of $Be$,$B$,$N$ and $O$ follow the order...

Which of the following relations is correct with respect to the first $(I)$ and second $(II)$ ionization potentials of sodium $(Na)$ and magnesium $(Mg)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module