What type of hybridization is involved in [Fe | vedclass

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Question

(A) In $[Fe(CN)_6]^{3-}$,the central metal ion is $Fe^{3+}$.The atomic number of $Fe$ is $26$,so the electronic configuration of $Fe^{3+}$ is $[Ar] 3d

Vedclass · Accepted Answer

$d^2sp^3$

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(A) In $[Fe(CN)_6]^{3-}$,the central metal ion is $Fe^{3+}$.The atomic number of $Fe$ is $26$,so the electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$.Since $CN^-$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals.This results in two empty $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals,which hybridize to form $d^2sp^3$ hybrid orbitals.Thus,the hybridization is $d^2sp^3$.

List-$I$ (Hybridisation)	List-$II$ (Compound/ion)
$A. sp^3d$	$I. [PtCl_4]^{2-}$
$B. sp^3d^2$	$II. SF_6$
$C. dsp^2$	$III. BCl_3$
$D. dsp^3$	$IV. PCl_5$
	$V. ClF_3$

What type of hybridization is involved in $[Fe(CN)_6]^{3-}$?

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Match the following:
List-$I$ (Hybridisation) List-$II$ (Compound/ion)
$A. sp^3d$ $I. [PtCl_4]^{2-}$
$B. sp^3d^2$ $II. SF_6$
$C. dsp^2$ $III. BCl_3$
$D. dsp^3$ $IV. PCl_5$
$V. ClF_3$

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