What type of isomerism is exhibited by [Cr(H_ | vedclass

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(B) The complexes $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$ differ in the number of water molecules directly coordinated to the central m

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Solvate

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(B) The complexes $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$ differ in the number of water molecules directly coordinated to the central metal ion $Cr^{3+}$ versus those present as lattice water (solvent of crystallization).This type of isomerism,where the solvent molecule (in this case,$H_2O$) acts as a ligand in one isomer and as a free solvent molecule in another,is known as solvate isomerism (also called hydrate isomerism).Therefore,the correct answer is $B$.

What type of isomerism is exhibited by $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$?

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