What volume of ethyl alcohol and water must b | vedclass

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(A) The concentration of a solution by volume is given by the formula:Concentration $(\% v/v) = \frac{	ext{Volume of solute}}{	ext{Total volume of s

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$125 \, mL$ of ethyl alcohol and $125 \, mL$ of water

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(A) The concentration of a solution by volume is given by the formula:Concentration $(\% v/v) = \frac{	ext{Volume of solute}}{	ext{Total volume of solution}} 	imes 100$Given,total volume of solution = $250 \, mL$ and concentration = $50 \%$.Let the volume of ethyl alcohol (solute) be $x \, mL$.$50 = \frac{x}{250} 	imes 100$$x = \frac{50 	imes 250}{100} = 125 \, mL$.Therefore,the volume of ethyl alcohol required is $125 \, mL$.The volume of water (solvent) required = Total volume - Volume of ethyl alcohol = $250 \, mL - 125 \, mL = 125 \, mL$.Thus,$125 \, mL$ of ethyl alcohol and $125 \, mL$ of water must be mixed.

What volume of ethyl alcohol and water must be mixed together to prepare $250 \, mL$ of $50 \%$ by volume of alcohol in water?

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