What will be the amount of MgCl_2 produced wh | vedclass

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(B) The balanced chemical equation is: $MgO + 2HCl \longrightarrow MgCl_2 + H_2O$ From the stoichiometry of the reaction,$2 \ mol$ of $HCl$ reacts to

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$22.12$

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(B) The balanced chemical equation is: $MgO + 2HCl \longrightarrow MgCl_2 + H_2O$ From the stoichiometry of the reaction,$2 \ mol$ of $HCl$ reacts to produce $1 \ mol$ of $MgCl_2$. Molar mass of $HCl = 1 + 35.5 = 36.5 \ g/mol$. Mass of $2 \ mol$ of $HCl = 2 	imes 36.5 = 73 \ g$. Molar mass of $MgCl_2 = 24 + 2 	imes 35.5 = 95 \ g/mol$. According to the reaction,$73 \ g$ of $HCl$ produces $95 \ g$ of $MgCl_2$. Therefore,$17 \ g$ of $HCl$ will produce: $\frac{95 \ g}{73 \ g} 	imes 17 \ g \approx 22.12 \ g$ of $MgCl_2$.

What will be the amount of $MgCl_2$ produced when $17 \ g$ of $HCl$ is reacted with an excess of $MgO$ in the following reaction?
$MgO + 2HCl \longrightarrow MgCl_2 + H_2O$

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What will be the amount of $MgCl_2$ produced when $17 \ g$ of $HCl$ is reacted with an excess of $MgO$ in the following reaction? $MgO + 2HCl \longrightarrow MgCl_2 + H_2O$