What will be the major product of each of the | vedclass

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(B) In reaction $1$,the quaternary ammonium hydroxide undergoes Hofmann elimination. Due to the steric bulk of the leaving group $-N^{+}(CH_3)_3$,the

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$1-Y, 2-X$

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(B) In reaction $1$,the quaternary ammonium hydroxide undergoes Hofmann elimination. Due to the steric bulk of the leaving group $-N^{+}(CH_3)_3$,the less substituted alkene,$1$-butene $(Y)$,is the major product. In reaction $2$,the alkyl halide undergoes dehydrohalogenation following Zaitsev's rule,where the more substituted alkene,$2$-butene $(X)$,is the major product. Therefore,the correct answer is $1-Y, 2-X$.

What will be the major product of each of the two reactions shown below?
$1.$ $CH_3-CH_2-CH(N^{+}(CH_3)_3)OH^{-} \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$
$2.$ $CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$

Similar Questions

Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$

The compound $B$ formed in the following sequence of reactions is:
$CH_3-CH_2-CH_2-OH$ $\xrightarrow{PCl_3} A$ $\xrightarrow{Alco. KOH} B$

Alkenes usually show which type of reaction?

For the reaction: $CH_2=CH-CH=CH_2 + HBr (1 \text{ eq}) \xrightarrow{80^{\circ}C} P_1 + P_2$ (where $P_1$ is the major product),identify $P_1$.

$CH_3-CH=CH_2 \xrightarrow{IBr} \text{Product } (A) \text{ is}$

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What will be the major product of each of the two reactions shown below? $1.$ $CH_3-CH_2-CH(N^{+}(CH_3)_3)OH^{-} \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$ $2.$ $CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$