What will be the major product of the followi | vedclass

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(C) Step $1$: The terminal alkyne $n-Bu-C \equiv CH$ reacts with $n-BuLi$ to form the acetylide anion $n-Bu-C \equiv C^- Li^+$.Step $2$: The acetylide

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(C) Step $1$: The terminal alkyne $n-Bu-C \equiv CH$ reacts with $n-BuLi$ to form the acetylide anion $n-Bu-C \equiv C^- Li^+$.Step $2$: The acetylide anion undergoes an $S_N2$ reaction with $n-C_5H_{11}Cl$ to form the internal alkyne $n-Bu-C \equiv C-C_5H_{11}$.Step $3$: The hydrogenation of the internal alkyne using $Lindlar$ catalyst and $H_2$ results in the formation of a $cis$-alkene.Therefore,the major product is the $cis$-isomer where the $n-Bu$ and $C_5H_{11}$ groups are on the same side of the double bond,which corresponds to option $C$.

What will be the major product of the following sequence of reactions?
$n-Bu-C \equiv CH \xrightarrow[(ii) \text{Lindlar cat.}, H_2]{(i) n-BuLi, n-C_5H_{11}Cl}$

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What will be the major product of the following sequence of reactions?$n-Bu-C \equiv CH \xrightarrow[(ii) \text{Lindlar cat.}, H_2]{(i) n-BuLi, n-C_5H_{11}Cl}$